Trigonometric Functions
When discussing functions of the form \(y = f(x)\), it is helpful to discuss the transformations that can be applied to the graphs of the basic functions. For example, remember that the graph of \(y = x^2 + 3\) is the graph of \(y = x^2\) that has been shifted up by 3 units, or that the graph of \(y = \sqrt{x + 2}\) is the graph of \(y = \sqrt{x}\) that has been shifted to the left by 2 units, or the graph of \(y = -5\ln{x}\) is the graph of \(y = \ln{x}\) that is reflected over the \(x\)-axis and stretched vertically by a facctor of 5. A quick summary of the relevant transformations is provided below.
The following video will illustrate how these transformations effect the shape of the graph of \(y = \sin{x}\).
For a function having the form \(y = a \sin{\left(k\left(x - b\right)\right)} + c\) or \(y = a \cos{\left(k\left(x - b\right)\right)} + c\), we can summarize the transformations as follows. Note that we have some new vocabulary too, but the idea is still the same.
Self-Check #1: What transformations have been applied to \(y = \cos{x}\) to get \(y = \cos(x-\pi) - 2\)? (Select the most appropriate response.)
(Answer: B) -- The inner expression \(x - \pi\) corresponds to a phase shift to the right of \(\pi\) units, going the opposite direction of the sign, while the outer expression \(- 2\) corresponds to a vertical shift downward of 2 units.
Self-Check #2: Which graph represents the 1-period portion of \(y = 3\sin{\left(x + \frac{\pi}{2}\right)}\)? (Select the most appropriate response.)
(Answer: A) -- We can disregard graphs B and C because they are 1-period graphs of \(\cos{x}\). The amplitude of 3 means the graph has been vertically stretched by a factor of 3, or that it is 3 times taller than the base \(y = \sin{x}\) graph. The \(x + \frac{\pi}{2}\) inner expression means it has also a phase shift to the left by \(\frac{\pi}{2}\). Graph D is close, but it is shifted to the right. Only graph A is shifted to the left by \(\frac{\pi}{2}\) and is 3 times taller than \(y = \sin{x}\).
Self-Check #3: Which graph represents the 1-period portion of \(y = -\frac{1}{2}\cos{x}\)? (Select the most appropriate response.)
(Answer: D) -- We can disregard graph A because it is a 1-period \(\sin{x}\) graph. We can disregard graph B because it is not reflected over the \(x\)-axis. The amplitude of \(\frac{1}{2}\) means the graph has been compressed vertically by a factor of 2, or that it is half as tall as the base \(y = \cos{x}\) graph. Only graph D has been reflected over the \(x\)-axis and is \(\frac{1}{2}\) as tall as \(y = \cos{x}\).
Self-Check #4: Which graph represents the 1-period portion of \(y = \sin(2x)\)? (Select the most appropriate response.)
(Answer: C) -- We can disregard graphs B and D because they are 1-period graphs of \(\cos{x}\). The \(2x\) inner expression means the graph has been compressed horizontally by a factor of 2, or that its 1-period length is half of its original length. Since a 1-period graph of \(\sin{x}\) is \(2\pi\), half of that would be \(\pi\). However, graph A is twice the orignal 1-period length, having a length of \(4\pi\). Only graph C has a 1-period length that is \(\frac{1}{2}\) of the base 1-period length of \(y = \sin{x}\).